Back in 2008, a man who established his reputation with
Baseball statistics was lionized as a political guru for correctly “predicting”
the winner of 49 of the 50 states. He
did this through aggregation of state polls, and a formula which, speaking
bluntly, was based heavily on subjective weighting of polls he liked. On his side, it’s true Silver was accurate in
2008. Silver, however, doesn’t like
anyone bringing up his results in the 2010 mid-term election. This year, Silver has announced that
President Obama has an almost ninety percent chance of winning
re-election. He has also, rather
dishonestly, tried to hedge his predictions by saying that turnout will decide
the actual odds (hidden well below his bold headline), and admitted that if the
state polls used invalid weighting on party participation, then the election
results may be very different from his forecast. His supporters have even gone so far in recent
days as to demand that Silver’s system be judged on the process rather than
whether his predictions come true.
Leaving all this aside, the question may reasonably be asked, about what
the odds really are for Obama and Romney.
There is a reasonable method available for determining those odds.
Whenever a percentage chance is given for something
happening, it claims that of a hundred possible outcomes, this one will happen
‘x’ number of times. So we can figure up
the odds by working out what each candidate needs, and how they could get there.
First, President Obama.
By this date, there’s really no doubt that the District of Columbia and
the following states will be won by Obama:
California, Connecticut, Delaware, Hawaii, Illinois, most of Maine,
Maryland, Massachusetts, New Jersey, New York, Rhode Island, Vermont, and
Washington. That gives Obama DC
plus 13 states, for 178 Electoral Votes, meaning he needs another 92 EV to win
re-election.
Next, Governor Romney.
There is no doubt that Romney will win the following states: Alabama, Alaska, Arizona, Arkansas, Florida,
Georgia, Idaho, Indiana, Kansas, Kentucky, Louisiana, Mississippi, Missouri,
Montana, Nebraska, North Dakota, Oklahoma, South Carolina, South Dakota,
Tennessee, Texas, Utah, West Virginia, and Wyoming. That gives Romney 24 states for 220 Electoral
Votes, meaning he needs another 50 EV to win the White House.
There are 13 battleground states plus 1 EV in Maine that is contested,
for 140 Electoral Votes. From the start
we can see that neither candidate needs to sweep all the battleground states to
win.
Before going on, there is a controversy which will sort
itself out tomorrow. Many state polls
have given heavy advantage in weighting to Democrats, even when previous
elections show no such disparity in voting by party. As a result, there is suspicion among
conservatives that the state polls are inaccurate in stating actual voter
support. So the question comes down to
whether turnout will be like 2008, 2004, or somewhere in between. For each of the states, therefore, we can
look at the actual part weights from 2004 and 2008, then use that to tell us
what we might see this year. Here’s how
each state plays out, starting with the highest EV states still contested:
08: Obama 04: Romney Mix:
Obama
08: Obama 04:
Romney Mix: Romney
08: Obama 04: Romney Mix:
Obama
08: Obama 04: Romney Mix: Romney
08: Obama 04: Romney Mix: Romney
08: Obama 04: Romney Mix:
Obama
08: Obama 04: Romney Mix: Romney
08: Obama 04: Romney Mix: Romney
08: Obama 04: Romney Mix:
Obama
08: Obama 04: Romney Mix:
Obama
08: Obama 04: Romney Mix:
Obama
08: Obama 04: Romney Mix:
Obama
08: Obama 04: Romney Mix: Romney
08: Obama 04: Romney Mix:
Obama
On the weights, assuming each of the three turnouts is
equally likely, then on average Obama would win 70.3 of the EV and Romney would
win 68.5. But since Obama needs 92 to
win, he has a net 38.2% chance of winning, while Romney (who only needs 50 more EV) has a net 61.8% chance
of winning.
That’s the math. The
votes themselves will decide the fact.
Be sure and vote.
No comments:
Post a Comment